Lab 1 Solutions
Solution Files
Additionally, please fill out this survey with any issues you might have faced in Lab 0 Python installation or if you used the Windows automated installer.
For quickly generating ok commands, you can now use the ok command generator.
Quick Logistics Review
Using Python
When running a Python file, you can use options on the command line to inspect your code further. Here are a few that will come in handy. If you want to learn more about other Python command-line options, take a look at the documentation.
Using no command-line options will run the code in the file you provide and return you to the command line. For example, if we want to run
lab00.py
this way, we would write in the terminal:python3 lab00.py
-i
: The-i
option runs your Python script, then opens an interactive session. In an interactive session, you run Python code line by line and get immediate feedback instead of running an entire file all at once. To exit, typeexit()
into the interpreter prompt. You can also use the keyboard shortcutCtrl-D
on Linux/Mac machines orCtrl-Z Enter
on Windows.If you edit the Python file while running it interactively, you will need to exit and restart the interpreter in order for those changes to take effect.
Here's how we can run
lab00.py
interactively:python3 -i lab00.py
-m doctest
: Runs doctests in a particular file. Doctests are surrounded by triple quotes ("""
) within functions.Each test in the file consists of
>>>
followed by some Python code and the expected output (though the>>>
are not seen in the output of the doctest command).To run doctests for
lab00.py
, we can run:python3 -m doctest lab00.py
Using OK
In 61A, we use a program called Ok for autograding labs, homeworks, and projects. You should have Ok in the starter files downloaded at the start of this lab. For more information on using Ok commands, learn more here.
You can quickly generate most ok commands at ok-help.
To use Ok to run doctests for a specified function, run the following command:
python3 ok -q <specified function>
By default, only tests that did not pass will show up. You can use the -v
option to show all tests, including tests you have passed:
python3 ok -v
You can also use the debug printing feature in OK by writing
print("DEBUG:", x)
Finally, when you have finished all the questions in
lab01.py, you must submit the assignment using the
--submit
option:
python3 ok --submit
Pair programming
You can use this lab as a way to try out pair programming. Check out the pair programming page.
Topics
Consult this section if you need a refresher on the material for this lab. It's okay to skip directly to the questions and refer back here should you get stuck.
Division, Floor Div, and Modulo
Let's compare the different division-related operators in Python 3:
True Division: / (decimal division) |
Floor Division: // (integer division) |
Modulo: % (remainder) |
---|---|---|
|
|
|
Notice that Python outputs ZeroDivisionError
for certain cases. We will go over this later in this lab under Error Messages.
One useful technique involving the %
operator is to check
whether a number x
is divisible by another number y
:
x % y == 0
For example, in order to check if x
is an even number:
x % 2 == 0
Functions
If we want to execute a series of statements over and over, we can abstract them away into a function to avoid repeating code.
For example, let's say we want to know the results of multiplying the numbers 1-3 by 3 and then adding 2 to it. Here's one way to do it:
>>> 1 * 3 + 2
5
>>> 2 * 3 + 2
8
>>> 3 * 3 + 2
11
If we wanted to do this with a larger set of numbers, that'd be a lot of repeated code! Let's write a function to capture this operation given any input number.
def foo(x):
return x * 3 + 2
This function, called foo
, takes in a single argument and will return the
result of multiplying that argument by 3 and adding 2.
Now we can call this function whenever we want this operation to be done:
>>> foo(1)
5
>>> foo(2)
8
>>> foo(1000)
3002
Applying a function to some arguments is done with a call expression.
Call expressions
A call expression applies a function, which may or may not accept arguments. The call expression evaluates to the function's return value.
The syntax of a function call:
add ( 2 , 3 )
| | |
operator operand operand
Every call expression requires a set of parentheses delimiting its comma-separated operands.
To evaluate a function call:
- Evaluate the operator, and then the operands (from left to right).
- Apply the operator to the operands (the values of the operands).
If an operand is a nested call expression, then these two steps are applied to that inner operand first in order to evaluate the outer operand.
return
and print
Most functions that you define will contain a return
statement. The return
statement will give the result of some computation back to the caller of the
function and exit the function. For example, the function square
below takes
in a number x
and returns its square.
def square(x):
"""
>>> square(4)
16
"""
return x * x
When Python executes a return
statement, the function terminates immediately.
If Python reaches the end of the function body without executing a return
statement, it will automatically return None
.
In contrast, the print
function is used to display values in the Terminal.
This can lead to some confusion between print
and return
because calling a
function in the Python interpreter will print out the function's return value.
However, unlike a return
statement, when Python evaluates a print
expression, the function does not terminate immediately.
def what_prints():
print('Hello World!')
return 'Exiting this function.'
print('61A is awesome!')
>>> what_prints()
Hello World!
'Exiting this function.'
Notice also that
return
will preserve the quotes.
Control
Boolean Operators
Python supports three boolean operators: and
, or
, and not
:
>>> a = 4
>>> a < 2 and a > 0
False
>>> a < 2 or a > 0
True
>>> not (a > 0)
False
and
evaluates toTrue
only if both operands evaluate toTrue
. If at least one operand isFalse
, thenand
evaluates toFalse
.or
evaluates toTrue
if at least one operand evaluates toTrue
. If both operands areFalse
, thenor
evaluates toFalse
.not
evaluates toTrue
if its operand evaluates toFalse
. It evaluates toFalse
if its operand evalutes toTrue
.
What do you think the following expression evaluates to? Try it out in the Python interpreter.
>>> True and not False or not True and False
It is difficult to read complex expressions, like the one above, and understand how a program will behave. Using parentheses can make your code easier to understand. Python interprets that expression in the following way:
>>> (True and (not False)) or ((not True) and False)
This is because boolean operators, like arithmetic operators, have an order of operation:
not
has the highest priorityand
or
has the lowest priority
Truthy and Falsey Values: It turns out and
and or
work on more than just booleans (True
,
False
). Python values such as 0
, None
, ''
(the empty string), and []
(the empty list) are considered false values. All other values are considered
true values.
Short Circuiting
What do you think will happen if we type the following into Python?
1 / 0
Try it out in Python! You should see a ZeroDivisionError
. But what about this expression?
True or 1 / 0
It evaluates to True
because Python's and
and or
operators short-circuit. That is, they don't necessarily evaluate every operand.
Operator | Checks if: | Evaluates from left to right up to: | Example |
---|---|---|---|
AND | All values are true | The first false value | False and 1 / 0 evaluates to False |
OR | At least one value is true | The first true value | True or 1 / 0 evaluates to True |
Short-circuiting happens when the operator reaches an operand that allows them to make a conclusion about the expression. For example, and
will short-circuit as soon as it reaches the first false value because it then knows that not all the values are true.
If and
and or
do not short-circuit, they just return the last
value; another way to remember this is that and
and or
always return the last
thing they evaluate, whether they short circuit or not. Keep in mind that and
and or
don't always return booleans when using values other than True
and False
.
If Statements
You can review the syntax of if
statements in
Section 1.5.4
of Composing Programs.
Tip: We sometimes see code that looks like this:
if x > 3: return True else: return False
This can be written more concisely as
return x > 3
. If your code looks like the code above, see if you can rewrite it more clearly!
While Loops
You can review the syntax of while
loops in
Section 1.5.5
of Composing Programs.
Error Messages
By now, you've probably seen a couple of error messages. They might look intimidating, but error messages are very helpful for debugging code. The following are some common types of errors:
Error Types | Descriptions |
---|---|
SyntaxError | Contained improper syntax (e.g. missing a colon after an if statement or forgetting to close parentheses/quotes) |
IndentationError | Contained improper indentation (e.g. inconsistent indentation of a function body) |
TypeError | Attempted operation on incompatible types (e.g. trying to add a function and a number) or called function with the wrong number of arguments |
ZeroDivisionError | Attempted division by zero |
Using these descriptions of error messages, you should be able to get a better idea of what went wrong with your code. If you run into error messages, try to identify the problem before asking for help. You can often Google unfamiliar error messages to see if others have made similar mistakes to help you debug.
For example:
>>> square(3, 3)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: square() takes 1 positional argument but 2 were given
Note:
- The last line of an error message tells us the type of the error. In the
example above, we have a
TypeError
. - The error message tells us what we did wrong -- we gave
square
2 arguments when it can only take in 1 argument. In general, the last line is the most helpful. - The second to last line of the error message tells us on which line the
error occurred. This helps us track down the error. In the example above,
TypeError
occurred atline 1
.
Required Questions
Reminder: Please fill out the Lab 0 setup survey (also included at the beginning of this assignment): here.
What Would Python Display? (WWPD)
Q1: WWPD: Control
Use Ok to test your knowledge with the following "What Would Python Display?" questions:
python3 ok -q control -u
Hint: Make sure your
while
loop conditions eventually evaluate to a false value, or they'll never stop! TypingCtrl-C
will stop infinite loops in the interpreter.
>>> def xk(c, d):
... if c == 4:
... return 6
... elif d >= 4:
... return 6 + 7 + c
... else:
... return 25
>>> xk(10, 10)
______23
>>> xk(10, 6)
______23
>>> xk(4, 6)
______6
>>> xk(0, 0)
______25
>>> def how_big(x):
... if x > 10:
... print('huge')
... elif x > 5:
... return 'big'
... elif x > 0:
... print('small')
... else:
... print("nothing")
>>> how_big(7)
______'big'
>>> how_big(12)
______huge
>>> how_big(1)
______small
>>> how_big(-1)
______nothing
>>> n = 3
>>> while n >= 0:
... n -= 1
... print(n)
______2
1
0
-1
Hint: Make sure your
while
loop conditions eventually evaluate to a false value, or they'll never stop! TypingCtrl-C
will stop infinite loops in the interpreter.
>>> positive = 28
>>> while positive:
... print("positive?")
... positive -= 3
______Infinite Loop
>>> positive = -9
>>> negative = -12
>>> while negative:
... if positive:
... print(negative)
... positive += 3
... negative += 3
______-12
-9
-6
Q2: WWPD: Veritasiness
Use Ok to test your knowledge with the following "What Would Python Display?" questions:
python3 ok -q short-circuit -u
>>> True and 13
______13
>>> False or 0
______0
>>> not 10
______False
>>> not None
______True
>>> True and 1 / 0 and False
______Error (ZeroDivisionError)
>>> True or 1 / 0 or False
______True
>>> True and 0
______0
>>> False or 1
______1
>>> 1 and 3 and 6 and 10 and 15
______15
>>> -1 and 1 > 0
______True
>>> 0 or False or 2 or 1 / 0
______2
>>> not 0
______True
>>> (1 + 1) and 1
______1
>>> 1/0 or True
______Error
>>> (True or False) and False
______False
Q3: Debugging Quiz
The following is a quick quiz on different debugging techniques that will be helpful for you to use in this class. You can refer to the debugging article to answer the questions.
Use Ok to test your understanding:
python3 ok -q debugging-quiz -u
Parsons Problems
To work on these problems, open the Parsons editor:
python3 parsons
Q4: Add in Range
Complete add_in_range
, which returns the sum of all integers between start
and stop
(inclusive).
def add_in_range(start, stop):
"""
>>> add_in_range(3, 5) # .Case 1
12
>>> add_in_range(1, 10) # .Case 2
55
"""
total = 0
while start <= stop:
total += start
start += 1
return total
Q5: Digit Position Match
A number has a digit-position match if the i
th-to-last
digit is i
. For example, 980
has the
0
th-to-last digit as 0
. Or 98276
has the 2
nd-to-last digit as a 2
.
Write a function that determine if a number n
has a
digit-position match at a k
th-to-last digit k
.
def digit_pos_match(n, k):
"""
>>> digit_pos_match(980, 0) # .Case 1
True
>>> digit_pos_match(980, 2) # .Case 2
False
>>> digit_pos_match(98276, 2) # .Case 3
True
>>> digit_pos_match(98276, 3) # .Case 4
False
"""
index = 0
while index < k:
n = n // 10
index = index + 1
return n % 10 == k
Code Writing Questions
Q6: Falling Factorial
Let's write a function falling
, which is a "falling" factorial
that takes two arguments, n
and k
, and returns the product of k
consecutive numbers, starting from n
and working downwards.
When k
is 0, the function should return 1.
def falling(n, k):
"""Compute the falling factorial of n to depth k.
>>> falling(6, 3) # 6 * 5 * 4
120
>>> falling(4, 3) # 4 * 3 * 2
24
>>> falling(4, 1) # 4
4
>>> falling(4, 0)
1
"""
total, stop = 1, n-k
while n > stop:
total, n = total*n, n-1
return total
Use Ok to test your code:
python3 ok -q falling
Q7: Sum Digits
Write a function that takes in a nonnegative integer and sums its digits. (Using floor division and modulo might be helpful here!)
def sum_digits(y):
"""Sum all the digits of y.
>>> sum_digits(10) # 1 + 0 = 1
1
>>> sum_digits(4224) # 4 + 2 + 2 + 4 = 12
12
>>> sum_digits(1234567890)
45
>>> a = sum_digits(123) # make sure that you are using return rather than print
>>> a
6
"""
total = 0
while y > 0:
total, y = total + y % 10, y // 10
return total
Use Ok to test your code:
python3 ok -q sum_digits
Submit
Make sure to submit this assignment by running:
python3 ok --submit
Extra Practice
These questions are optional and will not affect your score on this assignment. However, they are great practice for future assignments, projects, and exams. Attempting these questions can be valuable in helping cement your knowledge of course concepts.
Q8: WWPD: What If?
Use Ok to test your knowledge with the following "What Would Python Display?" questions:
python3 ok -q if-statements -u
Hint:
return
) does not cause the function to exit.
>>> def ab(c, d):
... if c > 5:
... print(c)
... elif c > 7:
... print(d)
... print('foo')
>>> ab(10, 20)
______10
foo
>>> def bake(cake, make):
... if cake == 0:
... cake = cake + 1
... print(cake)
... if cake == 1:
... print(make)
... else:
... return cake
... return make
>>> bake(0, 29)
______1
29
29
>>> bake(1, "mashed potatoes")
______mashed potatoes
'mashed potatoes'
Q9: K-Occurrence
Complete k_occurrence
, a function which returns the number of times the digit
k
appears in num
. 0 is considered to have no digits.
def k_occurrence(k, num):
"""
>>> k_occurrence(5, 10) # .Case 1
0
>>> k_occurrence(5, 5115) # .Case 2
2
>>> k_occurrence(0, 100) # .Case 3
2
>>> k_occurrence(0, 0) # .Case 4
0
"""
occurrences = 0
while num:
if num % 10 == k:
occurrences += 1
num = num // 10
return occurrences
To work on this problem, open the Parsons editor:
python3 parsons
Q10: Double Eights
Write a function that takes in a number and determines if the digits contain two adjacent 8s.
def double_eights(n):
"""Return true if n has two eights in a row.
>>> double_eights(8)
False
>>> double_eights(88)
True
>>> double_eights(2882)
True
>>> double_eights(880088)
True
>>> double_eights(12345)
False
>>> double_eights(80808080)
False
"""
prev_eight = False
while n > 0:
last_digit = n % 10
if last_digit == 8 and prev_eight:
return True
elif last_digit == 8:
prev_eight = True
else:
prev_eight = False
n = n // 10
return False
Use Ok to test your code:
python3 ok -q double_eights