Homework 2: Higher Order Functions
Due by 11:59pm on Thursday, February 3
Instructions
Download hw02.zip. Inside the archive, you will find
a file called hw02.py, along with a copy of the ok
autograder.
Submission: When you are done, submit with python3 ok
--submit
. You may submit more than once before the deadline; only the
final submission will be scored. Check that you have successfully submitted
your code on okpy.org. See Lab 0 for more instructions on
submitting assignments.
Using Ok: If you have any questions about using Ok, please refer to this guide.
Readings: You might find the following references useful:
Grading: Homework is graded based on correctness. Each incorrect problem will decrease the total score by one point. There is a homework recovery policy as stated in the syllabus. This homework is out of 2 points.
Required questions
Several doctests refer to these functions:
from operator import add, mul
square = lambda x: x * x
identity = lambda x: x
triple = lambda x: 3 * x
increment = lambda x: x + 1
Getting Started Videos
These videos may provide some helpful direction for tackling the coding problems on this assignment.
To see these videos, you should be logged into your berkeley.edu email.
Parsons Problems
To work on these problems, open the Parsons editor:
python3 parsons
Q1: Count Until Larger
Implement the function count_until_larger
. count_until_larger
takes in a positive integer num
. count_until_larger
counts the distance between the rightmost digit of num
and the nearest greater digit; to do so, the function counts digits from right to left. Once it encounters a digit larger than the rightmost digit, it returns that count. If no such digit exists, then the function returns -1
.
For example, 8117
has a rightmost digit of 7
and returns a count of 3
. 9118117
also returns a count of 3
: for both, the count stops at 8
.
0
should be treated as having no digits and returns a count of -1
.
Consult the following doctests for specific behaviors of count_until_larger
.
def count_until_larger(num):
"""
Complete the function count_until_larger that takes in a positive integer num.
count_until_larger examines the rightmost digit and counts digits from right to
left until it encounters a digit larger than the rightmost digit, then returns that count.
>>> count_until_larger(117) # .Case 1
-1
>>> count_until_larger(8117) # .Case 2
3
>>> count_until_larger(9118117) # .Case 3
3
>>> count_until_larger(8777) # .Case 4
3
>>> count_until_larger(22) # .Case 5
-1
>>> count_until_larger(0) # .Case 6
-1
"""
"*** YOUR CODE HERE ***"
Q2: Filter Sequence
Write a function filter_sequence
which takes in two integers, start
and stop
, as well as a function cond
, which takes in a single argument and outputs a boolean value. filter_sequence
returns the sum of all digits from start
to stop
(inclusive) for which cond
returns True
.
def filter_sequence(cond, start, stop):
"""
Returns the sum of numbers from start (inclusive) to stop (inclusive) that satisfy
the one-argument function cond.
>>> filter_sequence(lambda x: x % 2 == 0, 0, 10) # .Case 1
30
>>> filter_sequence(lambda x: x % 2 == 1, 0, 10) # .Case 2
25
"""
"*** YOUR CODE HERE ***"
Code Writing Questions
Q3: Hailstone
Douglas Hofstadter's Pulitzer-prize-winning book, Gödel, Escher, Bach, poses the following mathematical puzzle.
- Pick a positive integer
n
as the start. - If
n
is even, divide it by 2. - If
n
is odd, multiply it by 3 and add 1. - Continue this process until
n
is 1.
The number n
will travel up and down but eventually end at 1 (at least for
all numbers that have ever been tried -- nobody has ever proved that the
sequence will terminate). Analogously, a hailstone travels up and down in the
atmosphere before eventually landing on earth.
This sequence of values of n
is often called a Hailstone sequence. Write a
function that takes a single argument with formal parameter name n
, prints
out the hailstone sequence starting at n
, and returns the number of steps in
the sequence:
def hailstone(n):
"""Print the hailstone sequence starting at n and return its
length.
>>> a = hailstone(10)
10
5
16
8
4
2
1
>>> a
7
>>> b = hailstone(1)
1
>>> b
1
"""
"*** YOUR CODE HERE ***"
Hailstone sequences can get quite long! Try 27. What's the longest you can find?
Note that if
n == 1
initially, then the sequence is one step long.
Use Ok to test your code:
python3 ok -q hailstone
Curious about hailstones or hailstone sequences? Take a look at these articles:
- Check out this article to learn more about how hailstones work!
- In 2019, there was a major development in understanding how the hailstone conjecture works for most numbers!
Q4: Product
The summation(n, term)
function from the higher-order functions lecture adds
up term(1) + ... + term(n)
. Write a similar function called product
that
returns term(1) * ... * term(n)
.
def product(n, term):
"""Return the product of the first n terms in a sequence.
n: a positive integer
term: a function that takes one argument to produce the term
>>> product(3, identity) # 1 * 2 * 3
6
>>> product(5, identity) # 1 * 2 * 3 * 4 * 5
120
>>> product(3, square) # 1^2 * 2^2 * 3^2
36
>>> product(5, square) # 1^2 * 2^2 * 3^2 * 4^2 * 5^2
14400
>>> product(3, increment) # (1+1) * (2+1) * (3+1)
24
>>> product(3, triple) # 1*3 * 2*3 * 3*3
162
"""
"*** YOUR CODE HERE ***"
Use Ok to test your code:
python3 ok -q product
Q5: Accumulate
Let's take a look at how summation
and product
are instances of a more
general function called accumulate
, which we would like to implement:
def accumulate(merger, start, n, term):
"""Return the result of merging the first n terms in a sequence and start.
The terms to be merged are term(1), term(2), ..., term(n). merger is a
two-argument commutative function.
>>> accumulate(add, 0, 5, identity) # 0 + 1 + 2 + 3 + 4 + 5
15
>>> accumulate(add, 11, 5, identity) # 11 + 1 + 2 + 3 + 4 + 5
26
>>> accumulate(add, 11, 0, identity) # 11
11
>>> accumulate(add, 11, 3, square) # 11 + 1^2 + 2^2 + 3^2
25
>>> accumulate(mul, 2, 3, square) # 2 * 1^2 * 2^2 * 3^2
72
>>> # 2 + (1^2 + 1) + (2^2 + 1) + (3^2 + 1)
>>> accumulate(lambda x, y: x + y + 1, 2, 3, square)
19
>>> # ((2 * 1^2 * 2) * 2^2 * 2) * 3^2 * 2
>>> accumulate(lambda x, y: 2 * x * y, 2, 3, square)
576
>>> accumulate(lambda x, y: (x + y) % 17, 19, 20, square)
16
"""
"*** YOUR CODE HERE ***"
accumulate
has the following parameters:
term
andn
: the same parameters as insummation
andproduct
merger
: a two-argument function that specifies how the current term is merged with the previously accumulated terms.start
: value at which to start the accumulation.
For example, the result of accumulate(add, 11, 3, square)
is
11 + square(1) + square(2) + square(3) = 25
Note: You may assume that
merger
is commutative. That is,merger(a, b) == merger(b, a)
for alla
,b
, andc
. However, you may not assumemerger
is chosen from a fixed function set and hard-code the solution.
After implementing accumulate
, show how summation
and product
can both be
defined as function calls to accumulate
.
Important:
You should have a single line of code (which should be a return
statement)
in each of your implementations for summation_using_accumulate
and
product_using_accumulate
, which the syntax check will check for.
Use Ok to test your code:
python3 ok -q accumulate
python3 ok -q summation_using_accumulate
python3 ok -q product_using_accumulate
Submit
Make sure to submit this assignment by running:
python3 ok --submit
Bonus Questions
Homework assignments will also contain prior exam-level questions for you to take a look at. These questions have no submission component; feel free to attempt them if you'd like a challenge!
Note that exams from Spring 2020, Fall 2020, and Spring 2021 gave students access to an interpreter, so the question format may be different than other years. Regardless, the questions included remain good exam-level problems doable without access to an interpreter.
- Fall 2019 MT1 Q3: You Again [Higher Order Functions]
- Spring 2021 MT1 Q4: Domain on the Range [Higher Order Functions]
- Fall 2021 MT1 Q1b: tik [Functions and Expressions]